DataGridViewの入力エラーを捕獲する方法

DataGridViewの入力エラーを捕獲する方法
VB.NET

Private Sub dgv1_DataError(ByVal sender As Object, _
        ByVal e As DataGridViewDataErrorEventArgs) _
        Handles dgv1.DataError
    If Not (e.Exception Is Nothing) Then
        MessageBox.Show(Me, _
            String.Format("({0}, {1}) のセルエラー発生" + vbCrLf + vbCrLf + "{2}", _
                e.ColumnIndex, e.RowIndex, e.Exception.Message), "エラー発生", _
            MessageBoxButtons.OK, _
            MessageBoxIcon.Error)
    End If
End Sub

C#

private void dgv1_DataError(object sender,
    DataGridViewDataErrorEventArgs e)
{
    if (e.Exception != null)
    {
        MessageBox.Show(this,
            string.Format("({0}, {1}) セルエラー発生 \n\n {2}",
            e.ColumnIndex, e.RowIndex, e.Exception.Message),
            "エラー発生",
            MessageBoxButtons.OK, MessageBoxIcon.Error);
    }
}

セルの入力エラーで元の値に自動で戻す方法
VB.NET

Private Sub dgv1_DataError(ByVal sender As Object, _
        ByVal e As DataGridViewDataErrorEventArgs) _
        Handles dgv1.DataError
    e.Cancel = False
End Sub

C#

private void dgv1_DataError(object sender,
    DataGridViewDataErrorEventArgs e)
{
    e.Cancel = false;
}